35.5%设AgCl 占X AgBr占 Y(108X+108Y)/(143.5X+188Y)=60.4%X=0.26Y80Y/(143.5*0.26Y+188Y)=35.5%
有一纯氯化银和溴化银的混合物，其中含银质量分数为60.4%，求混合物中溴的质量分数？
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35.5%设AgCl 占X AgBr占 Y(108X+108Y)/(143.5X+188Y)=60.4%X=0.26Y80Y/(143.5*0.26Y+188Y)=35.5%
